4j^2+4c-15=0

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Solution for 4j^2+4c-15=0 equation:


Simplifying
4j2 + 4c + -15 = 0

Reorder the terms:
-15 + 4c + 4j2 = 0

Solving
-15 + 4c + 4j2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 4c + 15 + 4j2 = 0 + 15

Reorder the terms:
-15 + 15 + 4c + 4j2 = 0 + 15

Combine like terms: -15 + 15 = 0
0 + 4c + 4j2 = 0 + 15
4c + 4j2 = 0 + 15

Combine like terms: 0 + 15 = 15
4c + 4j2 = 15

Add '-4j2' to each side of the equation.
4c + 4j2 + -4j2 = 15 + -4j2

Combine like terms: 4j2 + -4j2 = 0
4c + 0 = 15 + -4j2
4c = 15 + -4j2

Divide each side by '4'.
c = 3.75 + -1j2

Simplifying
c = 3.75 + -1j2

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